Exercise
$sen\left(3z\right)dz+2ycos^{3\:}\left(3z\right)dy=0$
Step-by-step Solution
Learn how to solve trigonometric identities problems step by step online. Solve the differential equation sin(3z)dz+2ycos(3z)^3dy=0. We need to isolate the dependent variable z, we can do that by simultaneously subtracting 2y\cos\left(3z\right)^3dy from both sides of the equation. Group the terms of the differential equation. Move the terms of the z variable to the left side, and the terms of the y variable to the right side of the equality. Integrate both sides of the differential equation, the left side with respect to z, and the right side with respect to y. Solve the integral \int\frac{\sin\left(3z\right)}{\cos\left(3z\right)^3}dz and replace the result in the differential equation.
Solve the differential equation sin(3z)dz+2ycos(3z)^3dy=0
Final answer to the exercise
$z=\frac{\mathrm{arcsec}\left(\sqrt{-6y^2+c_1}\right)}{3},\:z=\frac{\mathrm{arcsec}\left(-\sqrt{- 6y^2+c_1}\right)}{3}$