$11+\frac{7}{9}n=4$
$\frac{\left(a^3\right)^7}{\left(b^4\right)^5}$
$\frac{x^3+6x+2}{x-3}$
$\frac{dy}{dx}=\frac{x^2+3}{4y^3}$
$\frac{dy}{dx}=\frac{2xy}{x^2+4}$
$\left(10y^{11}-5y\right)\left(10y^{11}+5y\right)$
$x^2+2ax+a^2=0$
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