$\int\left(1+6x\right)^3dx$
$\frac{2x-1}{3}\:\ge\:-6x+10$
$\frac{4^{8x+6}.16^{2x}}{64^{3x}}=1\:$
$-25x^2-200x-384$
$\int_0^2\left(2a+1\right)dx$
$\int x\sqrt{3x^2+4}dx$
$x^2+2=27$
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