$4x^2-29x^2+25$
$\frac{10^{10}}{10^5}$
$7\:+\:8\left(\:n\:-\:1\:\right)$
$\lim_{x\to3}\left(\frac{\left(x^2\:-\:5x\:-\:6\right)}{\left(2x\:-\:6\right)}\right)$
$q\:+\:13\:-\:6$
$n^4+10n^2a+25a^2$
$3x-\frac{5}{6}=\frac{13}{6}$
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