$-\frac{x^2+x-8}{\left(x-3\right)\left(x+5\right)}=\frac{x}{x-3}$
$\sqrt[3]{16a^3}b^9c^{12}$
$a^2+\:25a\:+\:100$
$\frac{2x^4+7x^3-4x^2-27x-18}{x+3}$
$-5\left(x+4\right)$
$\frac{\left(2x-1\right)\left(x+1\right)}{x-1}$
$6-5\ln x=8$
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