dydx=x2−3y2, y(0)=4\frac{dy}{dx}=\frac{x^2-3}{y^2},\:y\left(0\right)=4dxdy=y2x2−3,y(0)=4
∫2.7x2cos(x3)dx\int2.7x^2\cos\left(x^3\right)dx∫2.7x2cos(x3)dx
10−x≥3x+3010-x\ge3x+3010−x≥3x+30
4y′′+4y′+5y=04y''+4y'+5y=04y′′+4y′+5y=0
−3a + 5a − 7a + 7a-3a\:+\:5a\:-\:7a\:+\:7a−3a+5a−7a+7a
tan2x+1=csc2x\tan^2x+1=\csc^2xtan2x+1=csc2x
(95y2−10x4)2\left(\frac{9}{5}y^2-10x^4\right)^2(59y2−10x4)2
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