$2x^3-4x^2+4x$
$x+1=1$
$\left(5\:^{\frac{1}{2}}\right)^{-2}$
$\frac{u}{u^2-1}u$
$4\cdot2-5$
$\int\frac{3\cos\left(4x\right)}{\sin^2\left(4x\right)}dx$
$2x^4y^2+6x^3y-8x^2+4x$
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