$2\cdot256$
$\lim\:_{x\to\:2}\:\:\sqrt[5]{3x^2\:-2x}$
$x^3-2x+1=1$
$\int\left(-\frac{1}{y^2-6y+13}\right)dy$
$\int\sqrt[3]{\left(2x\right)}dx$
$x\sqrt{1+y^2}dx=dy$
$-\cos^3\left(\pi\right)$
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