$\int\left(\frac{37-11x}{\left(x+6\right)^2\left(x-5\right)}\right)dx$
$\frac{2-3\sec^2\left(2x\right)}{\tan^2\left(2x\right)+1}$
$\left(4x+2\left(-1+3x-2x^2\right)\right)$
$\left(12a+2z\right)\left(12a-2z\right)$
$4+-5+-1+-8$
$2\:-3\:7$
$-_{77-2}$
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