$\frac{dy}{dx}=\frac{3\tan\left(y\right)}{\sec\left(x\right)}$
$2\left(6x+2\right)''-2x\left(6x+2\right)'+\left(6x+2\right)=ax+b$
$\left(4a^2+5\right).\left(4a^2-2\right)$
$7x-4\ge4-x$
$b=\frac{1-a^3}{1-a}$
$x^2y^2+3y$
$\int\left(\frac{x+2}{x^3+2x^2+5x}\right)dx$
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