$x^2-5<=0$
$2x\left(x+1\right)+15>3\:x^2$
$4x^2-20x-24y=-97$
$\left(50\right)\left(3\right)\left(50\right)$
$\int_{\frac{\pi}{8}}^{\frac{\pi}{3}}\left(\frac{\sec^4\left(x\right)}{\tan^2\left(x\right)}\right)dx$
$-1=-1+sin\left(x\right)$
$\left|-9\right|-8$
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