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Exercise

k=(a−1)2+4(1+b)2−4(1+b)(a−1)k=\left(a-1\right)^2+4\left(1+b\right)^2-4\left(1+b\right)\left(a-1\right)

Step-by-step Solution

1

Expand the expression (1+b)2\left(1+b\right)^2 using the square of a binomial: (a+b)2=a2+2ab+b2(a+b)^2=a^2+2ab+b^2

Make diagrams like this with our diagram generator
k=(a−1)2+4(1+2b+b2)−4(1+b)(a−1)k=\left(a-1\right)^2+4\left(1+2b+b^{2}\right)-4\left(1+b\right)\left(a-1\right)

Final answer to the exercise

k=(a−1)2+4(1+2b+b2)−4(1+b)(a−1)k=\left(a-1\right)^2+4\left(1+2b+b^{2}\right)-4\left(1+b\right)\left(a-1\right)

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k=(a−1)2+4(1+b)2−4(1+b)(a−1)
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