$x^2+9x-4=0$

$3u-4-1+1-4uy$

$\frac{dy}{dx}\left(\frac{\left(\left(x^2+12\right)^5\left(x^3+17\right)^4\right)}{x-3}\right)$

$\left(4x^2+3b^3\right)^5$

$-8x+2x-16\:<-5x+7x$

$\lim_{x\to2}\left(\frac{\frac{1}{\sqrt{x}}-\frac{1}{\sqrt{2}}}{x-2}\right)$

$\lim_{x\to0}\left(\frac{3sin6x}{2x}\right)$