$\int_{-4}^0\left(x^4+3x^3-5\right)\left(x\right)dx$

$2\sin^4x-\sin^2x=0$

$46^2+68x+36$

$\frac{dy}{dx}=\frac{1}{3}\cdot\left(2x+2\right)\cdot\frac{1}{\left(y+1\right)^2}$

$-6+5x<\frac{5}{4}+6x$

$x\cdot y\cdot\left(1+x^2\right)\cdot\frac{dy}{dx}=\left(1+y\right)^2$

$=-\left(.64\:\cdot\:log2.64\:+\:.36\:\cdot\:log2\:.36\right)\:$