$\frac{dy}{dx}y=\left(x^2+10\right)^2\left(x^3+3\right)^3$
$\lim_{x\to-1}\left(\frac{y+1}{y^2+1}\right)$
$\frac{\tan\:\left(a\right)}{\sec\:\left(a\right)}$
$128\cdot128\:-\:1$
$1-29$
$11a-8a-2a-3a+5a$
$e^y\cdot ydy=\frac{1+e^{-2x}}{e^x}dx$
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