$\sqrt{4}-3^2$
$\left(6x^2+7x\right)^4$
$-3x^2+12=-5x^2+20$
$-4x-11>7+4x$
$f\left(x\right)=\sqrt[3]{\ln\left(x^3\right)}$
$\lim_{x\to0}\left(\frac{1+cpsx}{x}\right)$
$6g+20\:=\:2g+36$
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