$\int\frac{x^2+x}{\sqrt{x^2+4}}dx$
$\sqrt{\sqrt[3]{\left(a^3b^4\right)^2}}$
$\left(xy+2\right)\left(xy+4\right)$
$7\:\left(2h\:-\:3\right)$
$\frac{64m^6-1}{2m-m}$
$\int\frac{2x+2}{\left(x^2-4x+8\right)}dx$
$v-10=-9$
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