∫2x(x−1)(x+2)(x+5)dx\int\frac{2x}{\left(x-1\right)\left(x+2\right)\left(x+5\right)}dx∫(x−1)(x+2)(x+5)2xdx
∫abcdx\int _ { a } ^ { b } c d x∫abcdx
cos(e2x−y)=0\:cos\left(e^{2x}-y\right)=0cos(e2x−y)=0
x(2x+1)2x\left(2x+1\right)^2x(2x+1)2
xx−1=−2x−3 \frac{x}{x-1}=-\frac{2}{x-3}\:x−1x=−x−32
−63m3n39m2n5\frac{-63m^3n^3}{9m^2n^5}9m2n5−63m3n3
(8+9i)(8−9i)\left(8+9i\right)\left(8-9i\right)(8+9i)(8−9i)
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