$\left(\frac{\frac{2x^3}{3x}}{9}\right)$

$\frac{dy}{dx}=\frac{\left(x+2\right)}{3y^2}$

$\frac{3}{x-4}+\frac{3}{x+4}=\frac{24}{x^2-16}$

$4y+2\left(y+1\right)=y+5\left(y-3\right)$

$\int3x^2\left(4x^3-2\right)^3dx$

$y=\left(\frac{8x-x^{6}}{x^{3}}\right)^{-\frac{4}{5}}$

$f\left(x\right)=\frac{\left(2x\:-\:3\:\sqrt[3]{x^7}\:+\:3\:\right)\left(x^2\:-4\right)}{x^3}$