$6x-10=4x+4$
$\lim_{x\to\infty}\left(\frac{2}{e^{5x}-3}\right)$
$1+-6+36$
$y'+8xy=12xe^{\left(-x^2\right)}$
$da^2=-g$
$\:\frac{2b}{a+c}+\frac{c}{a+b}-\frac{a}{b+c}$
$y=\left(6-x\right)^{-3}$
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