$\frac{3}{2+4x}$
$\lim_{x\to5}\left(\frac{x^2-25}{\sqrt{x^2+11}}\right)$
$x^2+3x+2x+6$
$\lim_{x\to\infty}\left(\frac{tan\left(4x\right)}{ln\left(1+x\right)}\right)$
$20\:\cdot\:\left(-17\right)\:$
$f\left(4\right)=4\left(4\right)\frac{-10}{x-2}$
$-6,05+-3,611$
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