$x^2-4x^2-21$
$5\frac{1}{3}n^2^{+x}-7\frac{1}{2}m^3^{+2x}$
$\lim_{x\to4}\left(\frac{x^2-4}{3-\sqrt{x+7}}\right)$
$\left(8\cdot t+10\cdot s\right)^2$
$\sqrt{\left(h+1\right)^2-4}$
$x^2+11x+56$
$\left(6+12m^2\right)\left(6+m^2\right)$
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