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Exercise

$f\left(x\right)=\frac{\left(x+a\right)\left(x-b\right)}{\left(x-b\right)}$

Step-by-step Solution

1

Aplicamos a regra: $\frac{a}{a}$$=1$, onde $a=x-b$ e $a/a=\frac{\left(x+a\right)\left(x-b\right)}{x-b}$

$f\left(x\right)=x+a$

Final answer to the exercise

$f\left(x\right)=x+a$

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Main Topic: Equivalent Expressions

Two algebraic expressions are equivalent if they stay equal to each other, for any values their variables can take.

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