$-13-4+12-2+4+1$
$f\left(x\right)=\frac{1}{x^{2}-x}$
$\frac{dy}{dx}=yxe^{x+8}$
$x^2-1x+16$
$\frac{dy}{dx}+y=e^x,\:y\left(0\right)=1$
$\frac{4x^3-40x^2-12x+10}{x-2}$
$x=y^2-2$
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