$5x-\:4y\:-3y$
$12m^3n+72mn^4$
$3.24100\:-\:9.0126+1.41+00.197-12.14$
$\int\frac{x^2}{\left(x-4\right)^4}dx$
$1-4x>2-x$
$10+-20+80$
$\int_0^{\infty}-e^xdx$
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