$x^2\:+\:4x\:-\:20$
$\sqrt[3]{10^3}$
$x\left(\sqrt{x^2+1}-x\right)$
$3\left(b-4\right)=5b-2$
$2\left(-5-3\right)$
$x^2-3-6$
$\frac{dy}{dx}=\frac{\left(4+x\right)}{8+x}$
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