$\int\frac{6x+1}{x^3-8x^2+16x}dx$
$-4\cdot76$
$9=log\:2z$
$\int_{-4}^{\infty}\left(6e^{-2x}\right)dx$
$\left(3x-5\right)\left(4x+1\right)$
$\left(2-10+\left|5-\left(8+2\right)\right|\right)$
$\int\frac{x^3+x-2}{x+1}dx$
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