$\lim_{x\to\frac{\pi}{2}}\left(\pi-2x\right)\tan\left(x\right)$
$4-\infty$
$\left(13x^3-9y^5\right)\left(13x^3+9y^5\right)$
$\frac{sin\left(2x\right)}{\left(2x^2+x\right)}$
$65-\left(-78\right)=\:$
$\frac{x^2}{2}+2$
$\frac{c^6+2c^3-24}{c^4-4c^3+6c-24}$
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