$k=\frac{-p\cdot d'}{d}$
$-1^2-2$
$-a=1$
$\left(x^3+6\right)\left(x^4-8\right)$
$5x-1>3$
$\int_{27}^{\infty}\left(\frac{1}{\sqrt[3]{x}}\right)dx$
$\frac{6-n^2}{2-n}$
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