$2-3\left(\frac{18}{3}\right)^2$
$3x+y=0$
$\left(5x+3y-4z\right)^2$
$\left(3x^3-yz\right)^2$
$8x-65x=-x^2$
$x^2+14x+196$
$-3\left(x-4\right)=18$
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