$4x^2-6x+4\ge0$
$\frac{0,001^2\cdot0,1^{-2}}{100^{3^4}}$
$\int x\cdot\log\left(\frac{1}{x}\right)dx$
$\left(x-4y\right)\left(8x+y\right)$
$1-x^8$
$692=x+1$
$5x+5>30$
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