$\left(10y^4\:-\:5y^3\right)^2$
$\frac{7+x^3-x^4}{x^3+1}$
$x^2-5x-4\ge0$
$y=-\frac{3}{2}x^{\frac{7}{8}}$
$-\left(x+y\right)-3\left(x-y\right)+2$
$\left(439\right)^0$
$1^0+9^0-2^0+5^0+\left(-1\right)^0+1+1^0$
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