4(x−2y+3z)4\left(x-2y+3z\right)4(x−2y+3z)
∫sec2xtanx(tanx+1)dx\int\frac{sec^2x}{tanx\left(tanx+1\right)}dx∫tanx(tanx+1)sec2xdx
ddx8tt\frac{d}{dx}8t^{\sqrt{t}}dxd8tt
dzdx=1x2−2zx\frac{dz}{dx}=\frac{1}{x^2}-\frac{2z}{x}dxdz=x21−x2z
5x − 2(15 − x)5x\:-\:2\left(15\:-\:x\right)5x−2(15−x)
(4y + 9x) (4y − 9x)\left(4y\:+\:9x\right)\:\left(4y\:-\:9x\right)(4y+9x)(4y−9x)
(x−5)(xy′ +3y)=2\left(x-5\right)\left(xy'\:+3y\right)=2(x−5)(xy′+3y)=2
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