$25p^4+40p^2+16$
$\left(2x+3a\right)\left(2x-a\right)$
$\int\left(\left(5x+6\right)^{-1}\right)dx$
$\left(-9x^2\right)\left(\frac{3}{2}x^2\right)+\left(\frac{1}{2}x^3\right)\left(-18x\right)$
$3+5x\ge5x-1$
$6x^4+6x$
$5a+2a+2a-5a+3a-1=13$
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