$\frac{x}{x^2}=\frac{3}{x}$
$6xy\left(x-5y+2xy\right)$
$x\left(2x+2\right)$
$\left(-4sen\left(2x\right)\right)\left(cos\left(2x\right)\right)$
$121+21a\left(2\right)b\left(2\right)+a\left(4\right)b\left(4\right)$
$\frac{\left(2x^2+2\right)^3}{\left(x+1\right)\left(3x+2\right)}$
$x^2+3+5x=0$
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