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f(x)=cos(4x-3)−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

cos(4x−3)cos\left(4x-3\right)

Step-by-step Solution

1

Using the cosine of a sum formula: cos⁡(α±β)=cos⁡(α)cos⁡(β)∓sin⁡(α)sin⁡(β)\cos(\alpha\pm\beta)=\cos(\alpha)\cos(\beta)\mp\sin(\alpha)\sin(\beta), where angle α\alpha equals 4x4x, and angle β\beta equals −3-3

cos⁡(−3)cos⁡(4x)−sin⁡(−3)sin⁡(4x)\cos\left(-3\right)\cos\left(4x\right)-\sin\left(-3\right)\sin\left(4x\right)

Final answer to the exercise

cos⁡(−3)cos⁡(4x)−sin⁡(−3)sin⁡(4x)\cos\left(-3\right)\cos\left(4x\right)-\sin\left(-3\right)\sin\left(4x\right)

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cos(4x−3)
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