$2\cot^2\left(x\right)=4$
$\int2\:\sin\left(3x\right)\ln\left(\cos\left(3x\right)\right)dx$
$\frac{6x^38x-4}{2x^2}$
$\sqrt[3]{1}$
$\int\frac{8}{\left(x^4+4\right)}dx$
$\frac{x^2+3x+11}{x+1}$
$-6\cos^2x+2\cos x+2=3\cos x$
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