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Exercise

c=(sec⁡x+2cos⁡x)2+(2sec⁡x−cos⁡x)c=\left(\sec x+2\cos x\right)^2+\left(2\sec x-\cos x\right)

Step-by-step Solution

1

Expand the expression (sec⁡(x)+2cos⁡(x))2\left(\sec\left(x\right)+2\cos\left(x\right)\right)^2 using the square of a binomial: (a+b)2=a2+2ab+b2(a+b)^2=a^2+2ab+b^2

Make diagrams like this with our diagram generator
c=sec⁡(x)2+4sec⁡(x)cos⁡(x)+4cos⁡(x)2+2sec⁡(x)−cos⁡(x)c=\sec\left(x\right)^{2}+4\sec\left(x\right)\cos\left(x\right)+4\cos\left(x\right)^{2}+2\sec\left(x\right)-\cos\left(x\right)

Final answer to the exercise

c=sec⁡(x)2+4sec⁡(x)cos⁡(x)+4cos⁡(x)2+2sec⁡(x)−cos⁡(x)c=\sec\left(x\right)^{2}+4\sec\left(x\right)\cos\left(x\right)+4\cos\left(x\right)^{2}+2\sec\left(x\right)-\cos\left(x\right)

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