$16x^4-1$
$-8x^2y\left(-3x^5y^3\right)$
$x-17=-2$
$8\sqrt{x^3}-12$
$h ( x ) = x ^ { 3 } ( x - 1 ) ^ { 2 }$
$2x-8y-6y-9x$
$\frac{1}{y^{-1}}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!