$1-x'=\frac{x-1}{x-2}$
$\int\sin^4\left(x\right)\cdot\cos\left(x\right)dx$
$\left(6m+n\right)^3$
$-4a-5$
$33-\left(-75\right)$
$y^{'\:}=\sqrt{x+y+1}$
$4m^2-4m-3$
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