$m^7-1$
$\left(x\cdot2y-3z\right)^2$
$\lim_{x\to\infty}\left(1-\frac{4}{x}\right)^{1.3x}$
$\:x^2-6x-27=0$
$3a-7\left[\left(a-b\right)-2c\right]$
$\lim\:_{x\to\:\infty\:}\left(\frac{3x+4}{3x-2}\right)^{2x+1}$
$\left(x+6\right)y'=9y$
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