$$\frac{\left(x^3+7\right)}{\left(x^2+4x+3\right)}$$

$$\left(\frac{3^2\arctan\left(3\right)}{2}-\frac{3-\arctan\left(3\right)}{2}\right)-\left(\frac{\left(-2\right)^2\arctan\left(-2\right)}{2}-\frac{\left(-2\right)-\arctan\left(-2\right)}{2}\right)$$

$$64^{1\:}$$

$$\frac{\left(tan^2x-1\right)}{sinx+cosx}=\frac{\left(sinx-cosx\right)}{cos^2x}$$

$$\int\left(40-x\right)\cdot\cos\left(x\right)dx$$

$$3x-5<10$$

$$\ln\left(x\right)+\ln\left(x-1\right)=\ln\left(56\right)$$