$\lim\:_{x\to\:0}\frac{\left(4x^2+2x+1\right)}{\sin\left(x\right)}$
$\left(-3x^3+y^2\right)\left(2x^2+15x\right)\left(3x^2-5y\right)$
$\frac{3y-6}{2}>\frac{2y+5}{6}$
$8cos\left(-3x\right)sec\left(9x\right)$
$y'\:+\:2y\:=\:y^2\:+\:1$
$x^2\:+\:2x\:=\:3$
$\frac{880}{4}$
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