$20x^4-45x^2$
$\lim_{x\to0}\left(\frac{3sin6x}{2x}\right)$
$f\left(x\right)=\frac{1}{3}\sec^3\left(2x\right)-\sec\left(2x\right)$
$\left(\sec\left(a\right)^2\right)-\left(\tan\left(b\right)^2\right)$
$3\cdot\tan\left(x\right)+1=0$
$-5w^2+22w-8$
$x^2+2x>15$
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