$8a^2-24ab+18b^2$
$\lim_{x\to\infty}\left(\frac{\left(x^2-1\right)^2-x^2}{4-x^2}\right)$
$6x^2-4x+1$
$\int\left(4-2t^2\right)^7\cdot tdt$
$\left(\frac{3}{4}x^6r^2\right)\left(\frac{7}{2}p^4r^7\right)\left(\frac{2}{3}xq^2\right)$
$baba$
$-6-4r=6$
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