$\frac{dy}{dx}=\frac{\left(x+2\right)^2}{x^5}$
$2y-2yx-3y^2$
$\lim_{x,y\to0,0}\left(\frac{xy^3}{x^2+y^6}\right)$
$\left(1+2x\right)^{-\frac{1}{2}}$
$\frac{d}{dx}\left(3x^2\ln\left(x^2\right)-y^3=3+3xy^2\right)$
$\left(5xy-3x^2\right)^3$
$\frac{-4x^5+6x+8}{2x^2}$
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