$\log\left(x+3\right)^4=12$
$\int\left(\cos\left(5\right)x\right)dx$
$10\left(-9x^2-8x-5\right)$
$100a^4-60a^2b+ab^2$
$5\left(-1\right)^3\:+2\left(-1\right)^2\:\left(2\right)\:-\left(-1\right)\left(2\right)^2\:+4$
$0.2\frac{dx}{dt}+0.4x=e^{2t}$
$\left(2x^2+4\right).\left(x^2-4\right)$
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