$\left(1+4x^2\right)\frac{dy}{dx}=1$
$m^2\:x\:m^9\:x\:m^6$
$\left(-81\right)\left(-6\right)\left(2\right)\left(-3\right)$
$\frac{d}{dx}x^2+2xy+3y^2=4x$
$\int\frac{x^2-64}{x^2+64}dx$
$\left(6ab\:+\:9\right)\left(3a\:-\:2b\right)$
$-2^8$
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