$\lim_{x\to2}\left(\frac{x^2-3x-10}{x+2}\right)$
$\frac{d}{dx}\left(\frac{x^2\sqrt{2x+3}}{\left(x^2+4\right)^2}\right)$
$\left(4\left(3.1\right)-13\right)^{3.1}$
$2\left(-1\right)^3+3\left(-1\right)^2+3\left(-1\right)+1$
$12-3x>18x+5$
$-27-45-32-28$
$x^2-10x=0$
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