$\frac{5}{2}x+8;x=-3$
$\frac{\tan\left(a\right)}{\sec\left(a\right)}-\frac{\sec\left(a\right)}{\tan\left(a\right)}-\cos\left(a\right)$
$4.32^2$
$\frac{dy}{dx}=-2y=4$
$\frac{4x^4+8x^3+10x^2}{2x}$
$xy\cdot x^2y\cdot x^3y^2$
$\frac{9}{4}\left(\frac{10}{3}x-4\right)-\frac{1}{4}\left(2x-8\right)$
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